Q:

Write and solve an equation for each situation.9.In one baseball season, Peter hit twice the difference of thenumber of home runs Alice hit and 6. Altogether, they hit18 home runs. How many home runs did each player hitthat season?

Accepted Solution

A:
Answer:Peter 8 and Alice 10 home runs.Step-by-step explanation:Let the home runs by peter be represented by "x" and the home runs of Alice be represented by "y".Altogether the hit 18 home runs. This means sum of x and y would be 18. So we can write the equation as:x + y = 18                                      Equation 1Peter hit twice the difference of the  number of home runs Alice hit and 6. Difference of the  number of home runs Alice hit and 6 is y - 6 and twice of this difference would be 2(y - 6). So, we can set up the second equation as:x = 2(y - 6)                                     Equation 2Substituting the value of x from Equation 2 into Equation 1, we get:2(y - 6) + y = 182y - 12 + y = 183y = 30y = 10Substituting the value of y in Equation 2, we get:x = 2(y - 6) = 2(10 - 6) = 2(4) = 8This means, Peter hit 8 home runs and Alice hit 10 home runs.